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8 Comments

  1. Sir, in the second problem to actually verify superpositon theorem v total should also be calculated when all the sources are active which you didn’t mention there will you please explain the process involved there in detail?

    1. The superposition theorem is used not to verify but to solve complex electric circuits. To verify this theorem, you can either simulate the circuit in any simulation software or you can do it practically.
      In the superposition theorem, the current or voltage due to each individual source is determined and then they are added to find the resultant(total) current or voltage across the given load. The same is followed for both the problems.
      kindly check the above steps to solve.

  2. for problem 2, step (iv) can you please explain how/where the low resistance path works and why the 15 ohm resistor has a negligible resistance.
    thanks

    1. in step (iv), for the 5A source, there are two paths for the flow of current. One path is through 15Ω resistance and the other path is the short-circuited path, which is across the current source.
      In an electrical circuit, a short circuit will have very low resistance.
      Since there is very low resistance in this path, all the current from the source rushes through the short circuit path, making a negligible amount of current to flow through 15Ω resistance.
      That is the reason, I4 =0.
      And in your question, you have asked, “why the 15 ohm resistor has a negligible resistance.”
      15Ω resistor will never have negligible resistance. It has its own resistance of 15Ω.

  3. In part iv, to find for V4, you said the other current source is open-circuited but on the re-drawing of the circuit it is short-circuited.

    1. I don’t also understand why v4 in problem 2 is completely zero.
      I try using Ohms law for it, it was 0.060v.
      Can you help explain to me more better.